Score : $100$ points

问题描述

一天，高桥在$A$点过$B$分钟后准确地起床（按照24小时制计算），而青木在$C$点过$D$分1秒后准确地起床。

如果高桥比青木起床早，则输出Takahashi；否则，输出Aoki。

以上为通义千问 qwen-max 翻译，仅供参考。

Problem Statement

One day, Takahashi got up at exactly $B$ minutes past $A$ o'clock (in $24$-hour clock), and Aoki got up at exactly $D$ minutes and $1$ second past $C$ o'clock.
If Takahashi got up earlier than Aoki, print Takahashi; otherwise, print Aoki.

Constraints

• $0 \leq A \leq 23$
• $0 \leq B \leq 59$
• $0 \leq C \leq 23$
• $0 \leq D \leq 59$
• All values in input are integers.

Input

Input is given from Standard Input in the following format:

$A$ $B$ $C$ $D$

Output

If Takahashi got up earlier than Aoki, print Takahashi; otherwise, print Aoki.

Sample Input 1

7 0 6 30

Sample Output 1

Aoki

Takahashi got up at $7$ sharp, and Aoki got up at $30$ minutes and $1$ second past $6$ o'clock. Aoki was the first to get up, so Aoki should be printed.

Sample Input 2

7 30 7 30

Sample Output 2

Takahashi

Takahashi got up at exactly half past $7$, and Aoki got up at $30$ minutes and $1$ second past $7$ o'clock. Just by one second, Takahashi was the first to get up, so Takahashi should be printed.

Sample Input 3

0 0 23 59

Sample Output 3

Takahashi

$0:00$ in a day is one minute before $0:01$, not one minute past $23:59$ ("$24:00$"). Thus, Takahashi was the first to get up, so Takahashi should be printed.

update @ 2024/3/10 10:30:56