#abc200f. F - Minflip Summation
F - Minflip Summation
Score : points
问题描述
我们有一个由 0、1 和 ? 组成的字符串 。令  为将  连接  次得到的字符串。
通过将  中的每个 ? 替换为 0 或 1,我们可以得到  个不同的字符串,其中  是  中 ? 的数量。针对这些字符串中的每一个解决以下问题,并求出所有答案之和,结果对  取模。
让 表示通过替换 中的
?得到的字符串。我们将重复执行以下操作以使 中的所有字符变得相同。至少需要多少次操作才能实现这一点?
- 选择整数 和 ,满足 ,然后反转 中第 到第 个字符:即将
 0和1互换。
以上为通义千问 qwen-max 翻译,仅供参考。
Problem Statement
We have a string  consisting of 0, 1, and ?. Let  be the concatenation of  copies of .
By replacing each ? in  with 0 or 1, we can obtain  strings, where  is the number of ?s in . Solve the problem below for each of these strings and find the sum of all the answers, modulo .
Let be the string obtained by replacing
?in . We will repeatedly do the operation below to make all the characters in the same. At least how many operations are needed for this?
- Choose integers and such that , and invert the -th through -th characters of : from
 0and1and vice versa.
Constraints
Input
Input is given from Standard Input in the following format:
Output
Print the answer as an integer.
Sample Input 1
101
2
Sample Output 1
2
We have  101101, which does not contain ?, so we just need to solve the problem for the only  101101.
We can make all the characters the same in two operations as, for example, 101101  110011  111111.
We cannot make all the characters the same in one or fewer operations.
Sample Input 2
?0?
1
Sample Output 2
3
We have four candidates for : 000, 001, 100, and 101.
Sample Input 3
10111?10??1101??1?00?1?01??00010?0?1??
998244353
Sample Output 3
235562598
Since the answer can be enormous, find it modulo .
update @ 2024/3/10 09:12:29